The average speed of the train in meters per second on this journey, Time = 160 * 60 = 9600 sДistance travelled = 360 * 1000 = 360000 mДЄverage speed of the trains = 360000 / 9600 = 37.5 m/sД«. A train takes 2 hours and 40 minutes to travel a distance of 360 km. Distance and the speed of the coach = 21 * 360 = 7560 m, speed of the coach = distance / time = 7560 / 420 = 18m/sД¤. A coach takes seven minutes to travel the same distance. A car on a motorway travels a certain distance in six minutes at a speed of 21 m/s. it would take110 sec to travel a distance of 3300m at this speed, Time = distance / speed = 3300 / 30 = 110 secДЈ. Distance travelled = speed * time = 30 * 300 = 9000 mД¬. the average speed of the vehicle in m = 1800 / 60 = 30 m/sД«. A vehicle on a motorway travels 1800 m in 60s.ДЄ.

average speed of Z for the 1500s journey = total distance covered / total time takenДў.

Distance travelled by X in 1000 seconds = 30,000m It is calculated as the change in one quantity with respect to another quantity.Д«. the gradient of its distance-time graph is basically the slope of a graph. For an object travelling at constant speed the distance is the length travelled by an object from a particular point. This page also contains the link to the notes and video for the revision of this topic.Д©.1 Speed and Distance Time Graphs AQA GCSE Physics P9 Motion Kerboodle Answers : Page No. This page contains the AQA GCSE Physics P9 MotionВ Questions and kerboodle answers for revision and understanding.

Motion graph physics question